tegra124: add some explanatory text about U7.1 computations.

There's been a bit of confusion on this and the book is not helpful.

BUG=None
TEST=Just a comment, building is sufficient and it builds.
BUG=None

Change-Id: I497fe387238196602d57f178ba40eb4998ec2877
Signed-off-by: Ronald G. Minnich <rminnich@google.com>
Reviewed-on: https://chromium-review.googlesource.com/173910
Reviewed-by: Hung-Te Lin <hungte@chromium.org>
Commit-Queue: Ronald Minnich <rminnich@chromium.org>
Tested-by: Ronald Minnich <rminnich@chromium.org>
This commit is contained in:
Ronald G. Minnich 2013-10-21 11:30:11 -07:00 committed by chrome-internal-fetch
commit 822cad0cee

View file

@ -149,10 +149,46 @@ enum {
#define CLOCK_PLL_STABLE_DELAY_US 300
#define IO_STABILIZATION_DELAY (2)
/* Calculate clock fractional divider value from ref and target frequencies */
/* Calculate clock fractional divider value from ref and target frequencies.
* This is for a U7.1 format. This is not well written up in the book and
* there have been some questions about this macro, so here we go.
* U7.1 format is defined as (ddddddd+1) + (h*.5)
* The lowest order bit is actually a fractional bit.
* Hence, the divider can be thought of as 9 bits.
* So:
* divider = ((ref/freq) << 1 - 1) (upper 7 bits) |
* (ref/freq & 1) (low order half-bit)
* however we can't do fractional arithmetic ... these are integers!
* So we normalize by shifting the result left 1 bit, and extracting
* ddddddd and h directly to the returned u8.
* divider = 2*(ref/freq);
* We want to
* preserve 7 bits of divisor and one bit of fraction, in 8 bits, as well as
* subtract one from ddddddd. Since we computed ref*2, the dddddd is now nicely
* situated in the upper 7 bits, and the h is sitting there in the low order
* bit. To subtract 1 from ddddddd, just subtract 2 from the 8-bit number
* and voila, upper 7 bits are (ref/freq-1), and lowest bit is h. Since you
* will assign this to a u8, it gets nicely truncated for you.
*/
#define CLK_DIVIDER(REF, FREQ) ((((REF) * 2) / FREQ) - 2)
/* Calculate clock frequency value from reference and clock divider value */
/* Calculate clock frequency value from reference and clock divider value
* The discussion in the book is pretty lacking.
* The idea is that we need to divide a ref clock by a divisor
* in U7.1 format, where 7 upper bits are the integer
* and lowest order bit is a fraction.
* from the book, U7.1 is (ddddddd+1) + (h*.5)
* To normalize to an actual number, we might do this:
* ((d>>7+1)&0x7f) + (d&1 >> 1)
* but as you might guess, the low order bit would be lost.
* Since we can't express the fractional bit, we need to multiply it all by 2.
* ((d + 2)&0xfe) + (d & 1)
* Since we're just adding +2, the lowest order bit is preserved. Hence
* (d+2) is the same as ((d + 2)&0xfe) + (d & 1)
*
* Since you multiply denominator * 2 (by NOT shifting it),
* you multiply numerator * 2 to cancel it out.
*/
#define CLK_FREQUENCY(REF, REG) (((REF) * 2) / (REG + 2))
/* Warning: Some devices just use different bits for the same sources for no