libpaylod: fix lpgcc logic statement

The -z "${V}" sure must have meant to be -n "${V}", but come to think
of it, this check is not necessary, as the following check will
succeed if and only if V is set to 1.

BUG=none
TEST=verified that adding V=1 to the environment causes the lpgcc
     debug statements to show up in the output.

Change-Id: I1eb43ef49aeb4f16aef4fbee3a1037e853f9b40f
Signed-off-by: Vadim Bendebury <vbendeb@chromium.org>
Reviewed-on: https://chromium-review.googlesource.com/200501
Reviewed-by: Julius Werner <jwerner@chromium.org>
Reviewed-by: Marc Jones <marc.jones@se-eng.com>
This commit is contained in:
Vadim Bendebury 2014-05-19 15:43:47 -07:00 committed by chrome-internal-fetch
commit 7d69a292b1

View file

@ -27,7 +27,7 @@
## SUCH DAMAGE.
# GCC wrapper for libpayload
if [ -z "${V}" ] && [ "${V}" = 1 ]; then
if [ "${V}" = "1" ]; then
DEBUGME=1
else
DEBUGME=0